document.write( "Question 359930: Salem and Vernoville are 184 miles apart. A car leaves Salem Traveling towards Vernoville, and another car leaves Venoville at the same time traveling toward salem. The car leaving Salem averages 10 miles per hour more than the other, and they meet after 1 hour and 36 minutes. What is the average speed of cars?\r
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document.write( "The car leaving Salem average _______ mph
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document.write( "The car leaving Vernoville average ______mph
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document.write( "(round your answer to the nearest mile per hour) \n" );
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Algebra.Com's Answer #256821 by mananth(16949) You can put this solution on YOUR website! Salem bound car speed = x mph \n" ); document.write( "Vernonville bound car = x+10 mph \n" ); document.write( "distance = 144 miles \n" ); document.write( "... \n" ); document.write( "since they are travelling towards each other speed = 2x+10 mph \n" ); document.write( "time = distance/speed \n" ); document.write( "3/5 = 144/(2x+10) \n" ); document.write( "3*(2x+10)=144*5 \n" ); document.write( "6x+30 = 720 \n" ); document.write( "6x=720-30 \n" ); document.write( "6x=690 \n" ); document.write( "x= 115 mph salem bound car speed \n" ); document.write( "Vernonville bound car speed = 125 mph \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "The car leaving Salem averages mph? \n" ); document.write( "125 mph \n" ); document.write( "The car leaving Veronville averages mph? \n" ); document.write( "115mph\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |