document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=359923>Question 359923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter and area of a right triangle if one leg measures 10 ft. and the other leg measures 24 ft </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #256820 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=256820\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter and area of a right triangle if one leg measures 10 ft. and the other leg measures 24 ft<BR>\n" );
document.write( "use pythagoras theorem<BR>\n" );
document.write( "10^2+24^2= hypotenuse^2<BR>\n" );
document.write( "100+ 576=hypotenuse^2<BR>\n" );
document.write( "676 = hypo^2<BR>\n" );
document.write( "hypotenuse = 26<BR>\n" );
document.write( "...<BR>\n" );
document.write( "perimeter = 10+24+26 = 60 ft<BR>\n" );
document.write( "area = 1/2 * 10*24=120 ft^2<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );