document.write( "Question 359623: A Car travels 240 mi. A second car, traveling 12 mph faster than the first, makes the same trip in 1 hour less time. Find the speed of each car \n" ); document.write( "
Algebra.Com's Answer #256786 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A Car travels 240 mi. A second car, traveling 12 mph faster than the first, \n" ); document.write( " makes the same trip in 1 hour less time. Find the speed of each car \n" ); document.write( ": \n" ); document.write( "Let s = speed of the slower car \n" ); document.write( "then \n" ); document.write( "(s+12) = speed of the faster \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "Slow car time - fast car time = 1 hr \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply by s(s+12), results \n" ); document.write( "240(s+12) - 240s = s(s+12) \n" ); document.write( ": \n" ); document.write( "240s + 2880 - 240s = s^2 + 12s \n" ); document.write( "Combine as a quadratic equation on the right \n" ); document.write( "0 = s^2 + 12s - 2880 \n" ); document.write( "Factors to \n" ); document.write( "(s+60)(s-48) = 0 \n" ); document.write( "positive solution \n" ); document.write( "s = 48 mph is the speed of the slower car \n" ); document.write( "then \n" ); document.write( "48 + 12 = 60 mph is the faster car \n" ); document.write( ": \n" ); document.write( "Check solution by finding the times of each \n" ); document.write( " \n" ); document.write( " 5 - 4 = 1 hr; confirms our solutions \n" ); document.write( " |