document.write( "Question 359858: 2y^2 - x^2 = 1
\n" ); document.write( "y+1 = x\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #256770 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"2y%5E2+-+x%5E2+=+1\"
\n" ); document.write( "\"y%2B1+=+x\". substitute the bottom equation into the top equation:
\n" ); document.write( "\"2y%5E2+-%28y%2B1%29%5E2+=+1\",
\n" ); document.write( "\"2y%5E2+-y%5E2+-+2y-1+=+1\",
\n" ); document.write( "\"y%5E2+-2y-2+=+0\",
\n" ); document.write( "\"y+=+%282+%2B-+sqrt%28+2%5E2-4%2A1%2A%28-2%29+%29%29%2F%282%2A1%29\",
\n" ); document.write( "\"y+=+%282+%2B-+sqrt%28+12+%29%29%2F2\",
\n" ); document.write( "\"y+=+%282%2B-2sqrt%283%29%29%2F2\",
\n" ); document.write( "\"y+=+1%2B-sqrt%283%29\". Then \"x+=+2%2B-sqrt%283%29\".
\n" ); document.write( "
\n" );