document.write( "Question 359546: Jim and John drive from point A to point B in separate cars. Jim leaves at 6 am and arrives at 4 pm. John leaves at 10 am and arrives at 3 pm. Assume both men drive at constant speeds. Find when John catches up with Jim \n" ); document.write( "
Algebra.Com's Answer #256750 by ankor@dixie-net.com(22740)\"\" \"About 
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Jim and John drive from point A to point B in separate cars.
\n" ); document.write( " Jim leaves at 6 am and arrives at 4 pm. John leaves at 10 am and arrives at 3 pm.
\n" ); document.write( " Assume both men drive at constant speeds.
\n" ); document.write( " Find when John catches up with Jim.
\n" ); document.write( ":
\n" ); document.write( "Let d = distance from A to B
\n" ); document.write( "Jim's travel time: 10 hrs (6am to 4pm)
\n" ); document.write( "Jon's travel time: 5 hrs (10am to 4pm
\n" ); document.write( ":
\n" ); document.write( "Let t = Jon's travel time when he catches Jim
\n" ); document.write( "Then
\n" ); document.write( "(t+4) = Jim's travel time when this happens (Jim leave 4 hrs earlier)
\n" ); document.write( "and we know
\n" ); document.write( "\"d%2F10\" = Jim's speed
\n" ); document.write( "and
\n" ); document.write( "\"d%2F5\" = Jon's speed
\n" ); document.write( ":
\n" ); document.write( "When Jon catches Jim, they will have traveled the same distance; Dist = speed * time.
\n" ); document.write( "\"d%2F10\"(t+4) = \"d%2F5\"*t
\n" ); document.write( "multiply both sides by 10 to get rid of the denominators, results
\n" ); document.write( "d(t+4) = 2dt
\n" ); document.write( "divide both sides by d
\n" ); document.write( " t + 4 = 2t
\n" ); document.write( "4 = 2t - t
\n" ); document.write( "t = 4 hrs, Jon's travel time
\n" ); document.write( "then
\n" ); document.write( "4 + 4 = 8 hrs; Jim's travel time
\n" ); document.write( ":
\n" ); document.write( "10 am + 4 hrs = 2 pm when Jon overtakes Jim
\n" ); document.write( ":
\n" ); document.write( " \n" ); document.write( "
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