document.write( "Question 359732: Hello, could you please help me solve this equation. I initially tried solving by squaring both sides but the result seemed to be something awful. When I subtracted 4 from both sides and then squared both sides, my answer was x = 15/4
\n" ); document.write( "This is the equation:\r
\n" ); document.write( "\n" ); document.write( "4 + sqrt(10-x) = 6 + sqrt(4-x) solve for x
\n" ); document.write( "thank you.
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Algebra.Com's Answer #256730 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%2810-x%29+=+2+%2B+sqrt%284-x%29\"
\n" ); document.write( "\"10-x=4%2B4sqrt%284-x%29%2B%284-x%29\"
\n" ); document.write( "\"10-x=8-x%2B4sqrt%284-x%29\"
\n" ); document.write( "\"2=4sqrt%284-x%29\"
\n" ); document.write( "\"4=16%284-x%29\"
\n" ); document.write( "\"4=64-16x\"
\n" ); document.write( "\"16x=60\"
\n" ); document.write( "\"x=60%2F16\"
\n" ); document.write( "\"highlight%28x=15%2F4%29\"
\n" ); document.write( "Me too, well done.
\n" ); document.write( "You can always verify your answer by sticking it back in the equation.\r
\n" ); document.write( "\n" ); document.write( " \"4+%2B+sqrt%2810-15%2F4%29+=+6+%2B+sqrt%284-15%2F4%29++\"
\n" ); document.write( "\"4%2Bsqrt%28%2840-15%29%2F4%29=6%2Bsqrt%2816%2F4-15%2F4%29\"
\n" ); document.write( "\"4%2Bsqrt%2825%2F4%29=6%2Bsqrt%281%2F4%29\"
\n" ); document.write( "\"4%2B5%2F2=6%2B1%2F2\"
\n" ); document.write( "\"8%2F2%2B5%2F2=12%2F2%2B1%2F2\"
\n" ); document.write( "\"13%2F2=13%2F2\"
\n" ); document.write( "True, so the solution is verified.
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