document.write( "Question 359390: I was just wondering if someone could double check my work on this problem:
\n" ); document.write( "A box contains 8 good parts and 4 defective parts. If a sample of 2 parts is drawn from the box at random (without replacement), what is the probability of each of the following:\r
\n" ); document.write( "\n" ); document.write( "Two good parts are selected. (my answer 8/12 * 7/11 = 14/33 or 42%)
\n" ); document.write( "Two defective parts are selected. (my answer 4/12 * 3/11= 1/11 or 9%)
\n" ); document.write( "One good part is selected first, and then one defective part is selected second?
\n" ); document.write( "(my answer 8/12 or 66% chance of good part first, 4/11 or 36% chance of defective part being chosen second 8/12 * 4/11 = 8/33 or 24% totalling a 24% chance)
\n" ); document.write( "Exactly one defective part out of the two is selected. (my answer ?)
\n" ); document.write( "Any input would be apprieciated!
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Algebra.Com's Answer #256710 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
1.Two good parts are selected.
\n" ); document.write( "\"P%28G%2CG%29=14%2F33\" , Correct!
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\n" ); document.write( "2.Two defective parts are selected.
\n" ); document.write( "\"P%28D%2CD%29=1%2F11\", Correct!
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\n" ); document.write( "3.1st good, 2nd defective.
\n" ); document.write( "\"P%28G%2CD%29=8%2F33\", Correct!
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\n" ); document.write( "Exactly one defective part out of the two is selected.
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\n" ); document.write( "You already have half of the answer (\"P%28G%2CD%29=8%2F33\").
\n" ); document.write( "What about if you choose a defective part first, then a good part.
\n" ); document.write( "That would give you \"P%28D%2CG%29\"
\n" ); document.write( "P(exactly 1)=\"P%28D%2CG%29%2BP%28G%2CD%29\"
\n" ); document.write( "P(exactly 1)=\"P%28D%2CG%29%2B8%2F33\"
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\n" ); document.write( "Also,remember there are only 4 choices you can make, picking two parts.
\n" ); document.write( "GG-\"P%28G%2CG%29=14%2F33\"
\n" ); document.write( "DD-\"P%28D%2CD%29=1%2F11\"
\n" ); document.write( "GD-\"P%28G%2CD%29=8%2F33\"
\n" ); document.write( "DG-\"P%28D%2CG%29\"=??
\n" ); document.write( "Remember also that the sum of the probability for all of the events must be 1.
\n" ); document.write( "So you can solve this problem in two ways, or use the other way to check your work.\r
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