document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=359555>Question 359555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 160 cm , the length is 4 cm less than three times the width, find the length and width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #256563 by </B><A HREF=/tutors/aboutme.mpl?userid=Jk22><B>Jk22(389)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jk22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jk22><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=256563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l = 3w-4 : length equals 3 times width minus four<BR>\n" );
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document.write( "p = 2l + 2w = 6w - 8 + 2w = 8w - 8 = 160 <BR>\n" );
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document.write( " hence w - 1 = 20, w = 21 cm<BR>\n" );
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document.write( "=> l = 63 - 4 = 59 cm<BR>\n" );
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document.write( "Verification : p = 59*2 + 2*21 = 118 + 42 = 160 cm   </SPAN>\n" );
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