document.write( "Question 359548: Consider the series: 68, 81, x, 113, 132, find the value of x? \n" ); document.write( "

Algebra.Com's Answer #256547 by Fombitz(32388) $\"\"$ $\"About$

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Look at the first differences,
\n" ); document.write( " $\"d1=81-68=13\"$
\n" ); document.write( " $\"d2=x-81\"$
\n" ); document.write( " $\"d3=113-x\"$
\n" ); document.write( " $\"d4=132-11=19\"$
\n" ); document.write( "Looks like the second differences vary from each other by 2.
\n" ); document.write( "So the missing values should be 15 and 17.
\n" ); document.write( " $\"x-81=15\"$
\n" ); document.write( " $\"x=96\"$
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( " $\"113-x=17\"$
\n" ); document.write( " $\"x-96\"$
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( " $\"highlight%28x=96%29\"$ \n" ); document.write( "

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