document.write( "Question 359496: A boat cruises 36 mi against a 3-mph current and 36 mi back in the direction of the same current. The round trip takes 5 hours. What is the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #256501 by mananth(16946)\"\" \"About 
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let speed in still water = xmph
\n" ); document.write( "current speed = 3mph
\n" ); document.write( "upstream speed = x-3 mph
\n" ); document.write( "downstream speed = x+3 mph
\n" ); document.write( "...
\n" ); document.write( "time = distance / speed
\n" ); document.write( "36/(x+3)+36/(x-3)=5
\n" ); document.write( "36(x-3)+36(x+3)/(x+3)(x-3)=5
\n" ); document.write( "36x-108+36x+108=5(x^2-9)
\n" ); document.write( "36x+36x=5x^2-45
\n" ); document.write( "5x^2-72x-45=0
\n" ); document.write( "5x^2-75x+3x-45=0
\n" ); document.write( "5x(x-15)+3(x-15)=0
\n" ); document.write( "(x-15)(5x+3)=0
\n" ); document.write( "x=15 OR x=-3/5 ignore
\n" ); document.write( "x= 15 boat speed in still water
\n" ); document.write( ",...
\n" ); document.write( "m.ananth@hotmail.ca\r
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