document.write( "Question 359430: john drove to a distant city in 6 hour. When he returned there was less trafic and the trip only took 4 hours. If john averaged 38 mph faster on the return trip, how fast did he drive each way? \n" ); document.write( "
Algebra.Com's Answer #256476 by mananth(16946)\"\" \"About 
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forward let speed = xmph
\n" ); document.write( "time = 6 hours
\n" ); document.write( "distance = 6x miles
\n" ); document.write( "...
\n" ); document.write( "return
\n" ); document.write( "speed = x+38 mph
\n" ); document.write( "time =4 hours
\n" ); document.write( "distance = 4(x+38)
\n" ); document.write( "distance = same
\n" ); document.write( "6x=4(x+38)
\n" ); document.write( "6x=4x+152
\n" ); document.write( "6x-4x=152
\n" ); document.write( "2x=152
\n" ); document.write( "x=76 mph forward journey speed
\n" ); document.write( "76+38=114 mph return
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
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