document.write( "Question 359259: Hi, \r
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document.write( "Hello i am Vanessa my daughter is really having hard time with this and i would like to know what is the answer and how you got it so i could help her learn how to do it.My friend gave me this website just now and she and i dont know it please answer fast.\r
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document.write( "A number has 4 digits.
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document.write( "No digits in the number are repeated.
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document.write( "The digit in the tens place is three times the digit in the thousands place.
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document.write( "The number is odd.
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document.write( "The sum of the digits in the number is 27.
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document.write( "What is the number? \n" );
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Algebra.Com's Answer #256446 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A number has 4 digits. \n" ); document.write( "No digits in the number are repeated. \n" ); document.write( "The digit in the tens place is three times the digit in the thousands place. \n" ); document.write( "The number is odd. \n" ); document.write( "The sum of the digits in the number is 27. \n" ); document.write( "What is the number? \n" ); document.write( ": \n" ); document.write( "Let w = the thousands digit \n" ); document.write( "Let x = the 100's \n" ); document.write( "Let y = the 10's \n" ); document.write( "Let z = the units \n" ); document.write( ": \n" ); document.write( "The digit in the tens place is three times the digit in the thousands place. \n" ); document.write( "y = 3w \n" ); document.write( "Use some an assumption and some logic here \n" ); document.write( "With a total of 27, we have to assume one digit is 9, w has to be less than 4 \n" ); document.write( "let y = 9 \n" ); document.write( "then \n" ); document.write( "w = 3 \n" ); document.write( ": \n" ); document.write( "So we have: \n" ); document.write( "3 + x + 9 + z = 27 \n" ); document.write( "12 + x + z = 27 \n" ); document.write( "x + z = 27 - 15 \n" ); document.write( "x + z = 15 \n" ); document.write( "there are only 2 single digit pairs that add up to 15 \n" ); document.write( "6 & 9 \n" ); document.write( "7 & 8 \n" ); document.write( "we have already used 9 (no repeats), it must be 7 & 8 \n" ); document.write( "the last digit has to be odd, therefore we have \n" ); document.write( "x = 8 \n" ); document.write( "z = 7 \n" ); document.write( ": \n" ); document.write( "Our number: 3897 \n" ); document.write( " \n" ); document.write( " |