document.write( "Question 359168: The road from Tedium to Excitement is uphill for 5 miles, level for 4 miles, and then downhill for 6 miles. John Mayer walks from Excitement to Tedium in 4 hours. Later he walks halfway from Tedium to Excitement and back again in 3 hours and 55 minutes. Finally he walks all the way to Excitement from Tedium in 3 hours and 52 minutes. What are his rates going uphill, downhill, and on level ground assuming that these rates remain constant? \n" ); document.write( "
Algebra.Com's Answer #256442 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The road from Tedium to Excitement is uphill for 5 miles, level for 4 miles, \n" ); document.write( " and then downhill for 6 miles. \n" ); document.write( " John Mayer walks from Excitement to Tedium in 4 hours. \n" ); document.write( " Later he walks halfway from Tedium to Excitement and back again in 3 hours and 55 minutes. \n" ); document.write( " Finally he walks all the way to Excitement from Tedium in 3 hours and 52 minutes. \n" ); document.write( " What are his rates going uphill, downhill, and on level ground assuming that \n" ); document.write( " these rates remain constant? \n" ); document.write( ": \n" ); document.write( "Let u = uphill rate \n" ); document.write( "Let f = flat rate \n" ); document.write( "Let d = downhill rate \n" ); document.write( ": \n" ); document.write( "Write a time equation for each statement: Time = dist/rate \n" ); document.write( "We are going to do it in minutes, change it to hrs later \n" ); document.write( ": \n" ); document.write( "\"John Mayer walks from Excitement to Tedium in 4 hours.\" \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "\"he walks halfway from Tedium to Excitement and back again in 3 hours and 55 min.\" \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "\"he walks all the way to Excitement from Tedium in 3 hours and 52 minutes.\" \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " What are his rates going uphill, downhill, and on level ground assuming that these rates remain constant? \n" ); document.write( ": \n" ); document.write( "Use elimination on the 1st and 2nd equations \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-----------------------------------------Subtraction eliminates d \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply the 1st equation by 6 and the 3rd equation by 5 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------------------------------------------------Subtraction eliminates d again \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply the 1st 2 unknown equation by 10, add to the above equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------addition eliminates f, find u \n" ); document.write( " \n" ); document.write( "u = \n" ); document.write( "u = \n" ); document.write( ": \n" ); document.write( "Use the equation: \n" ); document.write( " \n" ); document.write( "20 - \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( "f = + \n" ); document.write( ": \n" ); document.write( "We can use the 1st equation, using hrs, to find d \n" ); document.write( " \n" ); document.write( "2 + 1 + 5/d = 4 \n" ); document.write( "5/d = 4 - 3 \n" ); document.write( "5/d = 1 \n" ); document.write( "d = 5 mph down hill \n" ); document.write( ": \n" ); document.write( "Summarize here \n" ); document.write( "u = 3 mph uphill \n" ); document.write( "f = 4 mph level \n" ); document.write( "d = 5 mph down hill \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if this works int he original 3rd equation, using hrs \n" ); document.write( " \n" ); document.write( "1.67 + 1 + 1.2 = 3.87 hrs which is 3 hrs, .87*60 = 52.2 min, close enough \n" ); document.write( " |