document.write( "Question 359168: The road from Tedium to Excitement is uphill for 5 miles, level for 4 miles, and then downhill for 6 miles. John Mayer walks from Excitement to Tedium in 4 hours. Later he walks halfway from Tedium to Excitement and back again in 3 hours and 55 minutes. Finally he walks all the way to Excitement from Tedium in 3 hours and 52 minutes. What are his rates going uphill, downhill, and on level ground assuming that these rates remain constant? \n" ); document.write( "
Algebra.Com's Answer #256442 by ankor@dixie-net.com(22740)\"\" \"About 
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The road from Tedium to Excitement is uphill for 5 miles, level for 4 miles,
\n" ); document.write( " and then downhill for 6 miles.
\n" ); document.write( " John Mayer walks from Excitement to Tedium in 4 hours.
\n" ); document.write( " Later he walks halfway from Tedium to Excitement and back again in 3 hours and 55 minutes.
\n" ); document.write( " Finally he walks all the way to Excitement from Tedium in 3 hours and 52 minutes.
\n" ); document.write( " What are his rates going uphill, downhill, and on level ground assuming that
\n" ); document.write( " these rates remain constant?
\n" ); document.write( ":
\n" ); document.write( "Let u = uphill rate
\n" ); document.write( "Let f = flat rate
\n" ); document.write( "Let d = downhill rate
\n" ); document.write( ":
\n" ); document.write( "Write a time equation for each statement: Time = dist/rate
\n" ); document.write( "We are going to do it in minutes, change it to hrs later
\n" ); document.write( ":
\n" ); document.write( "\"John Mayer walks from Excitement to Tedium in 4 hours.\"
\n" ); document.write( "\"6%2Fu\" + \"4%2Ff\" + \"5%2Fd\" = 240
\n" ); document.write( ":
\n" ); document.write( "\"he walks halfway from Tedium to Excitement and back again in 3 hours and 55 min.\"
\n" ); document.write( "\"5%2Fu\" + \"5%2Ff\" + \"5%2Fd\" = 235 (halfway is 7.5 mi)
\n" ); document.write( ":
\n" ); document.write( "\"he walks all the way to Excitement from Tedium in 3 hours and 52 minutes.\"
\n" ); document.write( "\"5%2Fu\" + \"4%2Ff\" + \"6%2Fd\" = 232
\n" ); document.write( ":
\n" ); document.write( " What are his rates going uphill, downhill, and on level ground assuming that these rates remain constant?
\n" ); document.write( ":
\n" ); document.write( "Use elimination on the 1st and 2nd equations
\n" ); document.write( "\"6%2Fu\" + \"4%2Ff\" + \"5%2Fd\" = 240
\n" ); document.write( "\"5%2Fu\" + \"5%2Ff\" + \"5%2Fd\" = 235
\n" ); document.write( "-----------------------------------------Subtraction eliminates d
\n" ); document.write( "\"1%2Fu\" - \"1%2Ff\" = 5
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st equation by 6 and the 3rd equation by 5
\n" ); document.write( "\"30%2Fu\" + \"30%2Ff\" + \"30%2Fd\" = 1410
\n" ); document.write( "\"25%2Fu\" + \"20%2Ff\" + \"30%2Fd\" = 1160
\n" ); document.write( "--------------------------------------------------Subtraction eliminates d again
\n" ); document.write( "\"5%2Fu\" + \"10%2Ff\" = 250
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st 2 unknown equation by 10, add to the above equation
\n" ); document.write( "\"5%2Fu\" + \"10%2Ff\" = 250
\n" ); document.write( "\"10%2Fu\" -\"10%2Ff\" = 50
\n" ); document.write( "------------------addition eliminates f, find u
\n" ); document.write( "\"15%2Fu\" = 300
\n" ); document.write( "u = \"15%2F300\"
\n" ); document.write( "u = \"1%2F20\" miles per minute, that's \"1%2F20\" * 60 = 3 mph up hill
\n" ); document.write( ":
\n" ); document.write( "Use the equation: \"1%2Fu\" - \"1%2Ff\" = 5 to find f,(were dealing mi/min here)
\n" ); document.write( "\"1%2F%281%2F20%29\" - \"1%2Ff\" = 5
\n" ); document.write( "20 - \"1%2Ff\" = 5
\n" ); document.write( "-\"1%2Ff\" = 5 - 20
\n" ); document.write( "\"-1%2Ff\" = -15
\n" ); document.write( "f = +\"1%2F15\" mi/min, that's \"1%2F15\" * 60 = 4 mph on the flat area
\n" ); document.write( ":
\n" ); document.write( "We can use the 1st equation, using hrs, to find d
\n" ); document.write( "\"6%2F3\" + \"4%2F4\" + \"5%2Fd\" = 4
\n" ); document.write( "2 + 1 + 5/d = 4
\n" ); document.write( "5/d = 4 - 3
\n" ); document.write( "5/d = 1
\n" ); document.write( "d = 5 mph down hill
\n" ); document.write( ":
\n" ); document.write( "Summarize here
\n" ); document.write( "u = 3 mph uphill
\n" ); document.write( "f = 4 mph level
\n" ); document.write( "d = 5 mph down hill
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if this works int he original 3rd equation, using hrs
\n" ); document.write( "\"5%2F3\" + \"4%2F4\" + \"6%2F5\" = 3 hr 52 min
\n" ); document.write( "1.67 + 1 + 1.2 = 3.87 hrs which is 3 hrs, .87*60 = 52.2 min, close enough
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