document.write( "Question 359349: the perimeter of a rectangle is 80 inches. its length is four times as long as it's width. what is the area of the rectangle \n" ); document.write( "
Algebra.Com's Answer #256428 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=4W \n" ); document.write( "2L+2W=P \n" ); document.write( "2*4W+2W=80 \n" ); document.write( "8W+2W=80 \n" ); document.write( "10W=80 \n" ); document.write( "W=80/10 \n" ); document.write( "W=8 ANS. FOR THE WIDTH. \n" ); document.write( "L=4*8=32 ANS FOR THE LENGTH.PROOF: \n" ); document.write( "2*32+2*8=80 \n" ); document.write( "64+16=80 \n" ); document.write( "80=80 \n" ); document.write( "AREA=8*32=256 IN^2 IS THE AREA.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |