document.write( "Question 359132: The point (-2,2) is a solution to the following linear system. Find the values for p and q.\r
\n" ); document.write( "\n" ); document.write( "-5px+(7q-1)y=-4
\n" ); document.write( "(p+10)x-(4q+1)y=-32 \n" ); document.write( "

Algebra.Com's Answer #256329 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


\n" );
document.write( "Hi,
\n" );
document.write( "1)Substituting (-2,2)in the first equation
\n" );
document.write( " -5p(-2)+(7q-1)*2=-4
\n" );
document.write( "10p+ 14q-2 =-4
\n" );
document.write( "10p+ 14q = -2\r
\n" );
document.write( "\n" );
document.write( "2)Substituting (-2,2)in the second equation
\n" );
document.write( "(p+10)(-2)-(4q+1)*2=-32
\n" );
document.write( "-20p - 8q - 2 = 32
\n" );
document.write( "-20p - 8q = 34
\n" );
document.write( "Multiplying first result by 2 and adding together
\n" );
document.write( "20p+ 28q = -4
\n" );
document.write( "-20p - 8q = 34
\n" );
document.write( "20q = 30
\n" );
document.write( "q = 3/2
\n" );
document.write( "10p + 21 = -2
\n" );
document.write( "p = -23/10
\n" );
document.write( "checking our answer
\n" );
document.write( "10*(-23/10) +14(3/2) = -23 + 21 = -2 \n" );
document.write( "

\n" );