document.write( "Question 40295: A comet follows a hyperbolic path about the focus of the Sun. The equation of the orbit is x squared/80 squared minus y squared/ 150 squared = 1, where x and y are measured in Gm. how far from the center of the hyperbola is the Sun. \n" ); document.write( "
Algebra.Com's Answer #25631 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A comet follows a hyperbolic path about the focus of the Sun. The equation of the orbit is x squared/80 squared minus y squared/ 150 squared = 1, where x and y are measured in Gm. how far from the center of the hyperbola is the Sun.\r \n" ); document.write( "\n" ); document.write( "a^2=150 \n" ); document.write( "b^2=80 \n" ); document.write( "c^2=a^2 + b^2 for a hyperbola \n" ); document.write( "c=sqrt(230) \n" ); document.write( "Vertex and comet position are at (a,0)=(sqrt(150),0) \n" ); document.write( "Focus and Sun position are at (c,0)=(sqrt(230),0) \n" ); document.write( "Distance from comet to Sun is sqrt(230)-sqrt(150)=2.918Gm \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |