document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=359151>Question 359151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a linear function f satisfies the conditions : f ( -3 ) = - 2 and f ( 3 ) = 16 , find f ( x ). \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #256309 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=256309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m=(y2-y1)/(x2-x1)=(16-(-2))/(3-(-3))=18/6=3\r<BR>\n" );
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document.write( "m=3<BR>\n" );
document.write( "x1=-3<BR>\n" );
document.write( "y1=-2\r<BR>\n" );
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document.write( "y-y1=m(x-x1)<BR>\n" );
document.write( "y-(-2)=3(x-(-3))<BR>\n" );
document.write( "y+2=3(x+3)<BR>\n" );
document.write( "y=3x+9-2<BR>\n" );
document.write( "y=3x+7\r<BR>\n" );
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document.write( "Answer: f(x) = 3x+7 </SPAN>\n" );
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