document.write( "Question 40216: Write the equation for the axis of symmetry of the graph of the equation y=5+16x-2x^2 (Hint: Rewrite the equation so that it fits the standard form of a quadratic function.) \n" ); document.write( "
Algebra.Com's Answer #25624 by venugopalramana(3286)\"\" \"About 
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Find the vertex of the graph of the equation y=5+16x-2x^2.
\n" ); document.write( "=-2(X^2-2.X*4+4^2)+2*4^2+5
\n" ); document.write( "=37-2(X-4)^2
\n" ); document.write( "VERTEX IS AT X-4=0....OR...X=4...AT X=4,WE HAVE Y=37..
\n" ); document.write( "HENCE VERTEX IS AT (4,37)
\n" ); document.write( "Show the algebraic steps used to solve this problem.\r
\n" ); document.write( "\n" ); document.write( "Miscellaneous_Word_Problems/40220: The vertex of a parabola is at (-4,-3). If one x-intercept is at (-11,0), what are the coordinates of the other x-intercept?
\n" ); document.write( "1 solutions
\n" ); document.write( "Answer 25622 by venugopalramana(1956) About Me on 2006-06-01 06:49:22 (Show Source):
\n" ); document.write( "The vertex of a parabola is at (-4,-3).
\n" ); document.write( "PARABOLA IS SYMMETRIC ABOUT VERTEX..SO X=-4 IS THE LINE OF SYMMETRY
\n" ); document.write( "If one x-intercept is at (-11,0),
\n" ); document.write( "DISTANCE OF THIS INTERCEPT POINT FROM X=-4 IS -11-(-4)=-7
\n" ); document.write( "HENCE THE OTHER INTERCEPTING POINT IS AT -4+7=3
\n" ); document.write( "what are the coordinates of the other x-intercept?
\n" ); document.write( "COORDINATES OF OTHER INTERCEPT = (3,0) \n" ); document.write( "
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