document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=359012>Question 359012</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A wire of length 16 inches is to be cut into two pieces; then each piece will be bent to form a square. Find the length of the two pieces assuming that the sum of the areas of the two squares is 10 square inches.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #256235 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=256235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one piece be x inches<BR>\n" );
document.write( "other piece will be 16-x inches\r<BR>\n" );
document.write( "\n" );
document.write( "..<BR>\n" );
document.write( "(x/4)^2+(16-x)/4 ^2=10<BR>\n" );
document.write( "x^2/16 +(256-32x+x^2)/16 =10<BR>\n" );
document.write( "x^2+256-32x+x^2=160<BR>\n" );
document.write( "2x^2-32x+96=0<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "x^2-16x+48=0<BR>\n" );
document.write( "(x-12)(x-4)=0<BR>\n" );
document.write( "x=12 OR x=4<BR>\n" );
document.write( "..<BR>\n" );
document.write( "the pieces are 12 & 4 inches<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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