document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=359039>Question 359039</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if you are traveling 330 and going 60 mph one way and comming back you are going 40 mph, what is your average speed of velocity? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #256222 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=256222\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=r*t or  r=d/t  where r=rate or speed, d=distance and t=time<BR>\n" );
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document.write( "To compute average rate you have to take Total distance divided by Total time<BR>\n" );
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document.write( "Total time there   t1=d/r=330/60=5.5hours<BR>\n" );
document.write( "Total time back  t2=d/r = 330/40=8.25 hours<BR>\n" );
document.write( "Total time round trip  t1+t2=5.5 + 8.25 = 13.75 hours<BR>\n" );
document.write( "Total distance =330+330 = 660<BR>\n" );
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document.write( "average trip rate (or speed) = 660/13.75=48.17 mph\r<BR>\n" );
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