document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40238>Question 40238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An equalateral triangle and a circle have the same center. The area of triangle not in the circle = the area of the circle not in the triangle. If the radius of the circle is 1 find the length of the side of the triangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25621 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An equalateral triangle and a circle have the same center. The area of triangle not in the circle = the area of the circle not in the triangle. If the radius of the circle is 1 find the length of the side of the triangle.<BR>\n" );
document.write( "WE HAVE FROM THE GIVEN DIPOITION OF THE FIGURE<BR>\n" );
document.write( "AREA OF EQ.TRIANGLE-AREA OF CIRCLE+AREA OF CIRCLE OUTSIDE TRIANGLE=AREA OF EQ.TRIANGLE OUTSIDE CIRCLE\r<BR>\n" );
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document.write( "BUT AREA OF EQ.TRIANGLE OUTSIDE CIRCLE=AREA OF CIRCLE OUTSIDE EQ.TRIANGLE<BR>\n" );
document.write( "AREA OF EQ.TRIANGLE-AREA OF CIRCLE =0<BR>\n" );
document.write( "HENCE AREA OF EQ.TRIANGLE=AREA OF CIRCLE<BR>\n" );
document.write( "IF SIDE OF EQ.TRIANGLE =B ...THEN<BR>\n" );
document.write( "B^2*SQRT(3)/4=PI*1*1=3.14<BR>\n" );
document.write( "B^2=4*3.14/SQRT(3)=4*3.14/1.732<BR>\n" );
document.write( "B=2.69 </SPAN>\n" );
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