document.write( "Question 359003: Find the mean and standard deviation of the following probability distribution:
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\n" ); document.write( " P(x)
\n" ); document.write( " 0.1
\n" ); document.write( " 0.2
\n" ); document.write( " 0.7
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\n" ); document.write( "Please show all of your work.
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Algebra.Com's Answer #256180 by robertb(5830)\"\" \"About 
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Mean = \"mu+=+1%2A0.1+%2B+2%2A0.2+%2B+3%2A0.7+=+2.6\"
\n" ); document.write( "Variance = \"sigma%5E2+=+%281-2.6%29%5E2%2A0.1++%2B+%282-2.6%29%5E2%2A0.2+%2B+%287-2.6%29%5E2%2A0.7\"
\n" ); document.write( "=\"2.56%2A0.1%2B0.36%2A0.2%2B19.36%2A0.7+=+13.88\".
\n" ); document.write( "Thus ,
\n" ); document.write( "standard deviation = \"sigma+=+sqrt%2813.88%29+=+3.7256\", to four decimal places.
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