document.write( "Question 358878: solve the equation on the interval (0,2pi)
\n" ); document.write( "tan (x/3) = root 3
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Algebra.Com's Answer #256179 by robertb(5830)\"\" \"About 
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\"tan+%28x%2F3%29+=+sqrt%283%29\",
\n" ); document.write( "\"%28tan+%28x%2F3%29%29%5E2+=+3\",after both sides.
\n" ); document.write( "\"1%2B%28tan+%28x%2F3%29%29%5E2+=+4\",
\n" ); document.write( "\"%28sec+%28x%2F3%29%29%5E2+=+4\", by a Pythagorean identity.
\n" ); document.write( "\"%28cos%28x%2F3%29%29%5E2+=+1%2F4\", after taking reciprocals.
\n" ); document.write( "\"cos%28x%2F3%29+=+1%2F2\" or\"cos%28x%2F3%29+=-+1%2F2\".
\n" ); document.write( "The first equation gives \"x%2F3+=+pi%2F3\", the second \"x%2F3+=+%284%2Api%29%2F3\".
\n" ); document.write( "further simplification gives \"x+=+pi\" and \"x+=+4%2Api\". The second answer is not acceptable, therefore the final answer is \"x+=+pi\".
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