document.write( "Question 358876: use an identity to solve the equation: six^2x -cosx+3=0 \n" ); document.write( "

Algebra.Com's Answer #256177 by robertb(5830) $\"\"$ $\"About$

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$\"+%28sinx%29%5E2+-+cosx%2B3=0\"$ ,
\n" ); document.write( " $\"1-%28cosx%29%5E2+-+cosx%2B3=0\"$ ,after using the Pythagorean identity.
\n" ); document.write( " $\"-%28cosx%29%5E2+-cosx%2B4=0\"$ ,
\n" ); document.write( " $\"%28cosx%29%5E2+%2Bcosx-4=0\"$ .
\n" ); document.write( "Applying the quadratic formula,
\n" ); document.write( " $\"cosx+=+%28-1+%2B-+sqrt%28+1%5E2-4%2A1%2A-4+%29%29%2F%282%2A1%29\"$ ,
\n" ); document.write( " $\"cosx+=+%28-1%2B-sqrt%2817%29%29%2F2\"$ .
\n" ); document.write( "However, these values are greater than 1, and also less than -1. Therefore the trigonometric equation does not have roots. \n" ); document.write( "

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