document.write( "Question 358967: 1)find three consecutive odd integers such that three times the first is 83 more than the sum of the second and the third \r
\n" ); document.write( "\n" ); document.write( "2)find four consecutive integers such that the sum of the last three integers is 20 more than two times the first \n" ); document.write( "
Algebra.Com's Answer #256172 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
1)find three consecutive odd integers such that three times the first is 83 more than the sum of the second and the third
\n" ); document.write( "let the integers be x,x+2,x+4
\n" ); document.write( "3x= 83+x+2+x+4
\n" ); document.write( "3x=89+2x
\n" ); document.write( "3x-2x=89
\n" ); document.write( "x= 89
\n" ); document.write( "...
\n" ); document.write( "89,91,93\r
\n" ); document.write( "\n" ); document.write( "2)find four consecutive integers such that the sum of the last three integers is 20 more than two times the first
\n" ); document.write( "let the integers be x,x+1,x+2,x+3
\n" ); document.write( "...
\n" ); document.write( "x+1+x+2+x+3=2x+20
\n" ); document.write( "3x+6=2x+20
\n" ); document.write( "3x-2x=20-6
\n" ); document.write( "x=14
\n" ); document.write( "...
\n" ); document.write( "14,15,16,17
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
\n" );