document.write( "Question 40251This question is from textbook College Algebra
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document.write( ": f(x)=x^2-2x\r
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document.write( "a) Find the average rate of change of f from 1 to x.
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document.write( " f(x) - f(1)
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document.write( " --------- (x does not = 1)
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document.write( " x - 1
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document.write( "b) Use result from part (a) to compute the average rate of change from x = 1 to x = 2.
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document.write( "c) Find an equation of the secant line containing (1, f(1)) and (2, f(2)) \n" );
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Algebra.Com's Answer #25617 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! f(x)=x^2-2x \n" ); document.write( "a) Find the average rate of change of f from 1 to x. \n" ); document.write( "f(x) - f(1) \n" ); document.write( "--------- (x does not = 1) \n" ); document.write( "x - 1 \n" ); document.write( "AVG R.O.C.={(X^2-2X)-(1^2-2*1)}/(X-1)=(X^2-2X+1)/(X-1)=(X-1)^2/(X-1)...SINCE X IS NOT EQUAL TO 1,WE CAN DIVIDE WITH X-1 TO GET \n" ); document.write( "R.O.C.=(X-1)\r \n" ); document.write( "\n" ); document.write( "b) Use result from part (a) to compute the average rate of change from x = 1 to x = 2. \n" ); document.write( "R.O.C.AT X=2.... \n" ); document.write( "2-1=1\r \n" ); document.write( "\n" ); document.write( "c) Find an equation of the secant line containing (1, f(1)) and (2, f(2)) \n" ); document.write( "EQN IS \n" ); document.write( "(Y-F(1)}/{F(2)-F(1)}={(X-1)/(2-1)} \n" ); document.write( "F(1)=1^2-2*1=-1 \n" ); document.write( "F(2)=2^2-2*2=0 \n" ); document.write( "SUBSTITUTING \n" ); document.write( "(Y+1)/1=(X-1)/(2-1)=X-1 \n" ); document.write( "Y+1=X-1 \n" ); document.write( "Y=X-2 \n" ); document.write( " |