document.write( "Question 358990: A man wants to see his girlfriend who lives 6 miles away. He leaves his house for her house at 6 am and walks at 4 miles an hour. When he leaves, he also sends a pigeon to her house. The bird flies at 30 miles an hour. When the bird reaches her house,she walks toward him at 2 miles an hour. When will they meet on the way? \n" ); document.write( "
Algebra.Com's Answer #256157 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A man wants to see his girlfriend who lives 6 miles away. He leaves his house for her house at 6 am and walks at 4 miles an hour. When he leaves, he also sends a pigeon to her house. The bird flies at 30 miles an hour. When the bird reaches her house,she walks toward him at 2 miles an hour. When will they meet on the way? \n" ); document.write( "........... \n" ); document.write( "pigeon's speed = 30 mph \n" ); document.write( "distance = 6 miles to her house \n" ); document.write( "time taken by pigeon = 6/30 = 1/5 hour. = 12 minutes \n" ); document.write( ".. \n" ); document.write( "speed man walks = 4mph \n" ); document.write( "in 1/5 hour he will walk 4/5 miles. \n" ); document.write( "... \n" ); document.write( "balance distance to her house = 6-4/5 \n" ); document.write( "=26/5 miles. \n" ); document.write( ".. \n" ); document.write( "man's speed = 4mph \n" ); document.write( "woman's speed = 2mph \n" ); document.write( "they are walking towards each other \n" ); document.write( "so speed = 6 mph. \n" ); document.write( "... \n" ); document.write( "distance = 26/5 miles \n" ); document.write( "speed = 6mph \n" ); document.write( "time = (26/5)/6 \n" ); document.write( "=26/5 *1/6 \n" ); document.write( "=26/30 hours \n" ); document.write( "= 52 minutes + 12 minutes= 64 minutes \n" ); document.write( "they meet at 7.04 am. \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |