document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=358922>Question 358922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man age is 4 times the combine age of his 2 son one of whom is 3 times as old as the other in 24 years their combine ages will be in 12 years less than their father age. what are their age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #256112 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=256112\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one son's age =x<BR>\n" );
document.write( "the other son's age =3x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "father's age = 4(x+3x)<BR>\n" );
document.write( "=16x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "after 24 years<BR>\n" );
document.write( "son x+24<BR>\n" );
document.write( "other son 3x+24<BR>\n" );
document.write( "Father = 16x+24<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x+24+3x+24=16x+24-12<BR>\n" );
document.write( "4x+48=16x+12<BR>\n" );
document.write( "16x-4x=48-12<BR>\n" );
document.write( "12x=36<BR>\n" );
document.write( "/12<BR>\n" );
document.write( "x=3 years one son's age<BR>\n" );
document.write( "second son's age = 3x= 9 years<BR>\n" );
document.write( "father's age = 16x = 48 years<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );