document.write( "Question 358579: A zebra can run30 mph. A tiger can run 50 mph.if the tiger has run 70 miles further than the zebra, how many minutes have they been running \n" ); document.write( "
Algebra.Com's Answer #256074 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A zebra can run 30 mph. \n" ); document.write( " A tiger can run 50 mph. \n" ); document.write( "If the tiger has run 70 miles further than the zebra, how many minutes have \n" ); document.write( " they been running \n" ); document.write( ": \n" ); document.write( "Let t = no. of hrs they have been running \n" ); document.write( ": \n" ); document.write( "Let z = no. of miles run by the zebra \n" ); document.write( "then \n" ); document.write( "(z+70) = no. of miles run by the tiger \n" ); document.write( ": \n" ); document.write( "Write two distance equations \n" ); document.write( "30t = z \n" ); document.write( "and \n" ); document.write( "50t = (z+70) \n" ); document.write( "Replace z with 30t \n" ); document.write( "50t = 30t + 70 \n" ); document.write( "50t - 30t = 70 \n" ); document.write( "20t = 70 \n" ); document.write( "t = \n" ); document.write( "t = 3.5 hrs \n" ); document.write( "but they want it in minutes: 3.5 * 60 = 210 minutes \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the distances \n" ); document.write( "3.5(50) = 175 mi \n" ); document.write( "3.5(30) = 105 mi \n" ); document.write( "----------------- \n" ); document.write( "differs: 70 mi \n" ); document.write( " |