document.write( "Question 358579: A zebra can run30 mph. A tiger can run 50 mph.if the tiger has run 70 miles further than the zebra, how many minutes have they been running \n" ); document.write( "
Algebra.Com's Answer #256074 by ankor@dixie-net.com(22740)\"\" \"About 
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A zebra can run 30 mph.
\n" ); document.write( " A tiger can run 50 mph.
\n" ); document.write( "If the tiger has run 70 miles further than the zebra, how many minutes have
\n" ); document.write( " they been running
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\n" ); document.write( "Let t = no. of hrs they have been running
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\n" ); document.write( "Let z = no. of miles run by the zebra
\n" ); document.write( "then
\n" ); document.write( "(z+70) = no. of miles run by the tiger
\n" ); document.write( ":
\n" ); document.write( "Write two distance equations
\n" ); document.write( "30t = z
\n" ); document.write( "and
\n" ); document.write( "50t = (z+70)
\n" ); document.write( "Replace z with 30t
\n" ); document.write( "50t = 30t + 70
\n" ); document.write( "50t - 30t = 70
\n" ); document.write( "20t = 70
\n" ); document.write( "t = \"70%2F20\"
\n" ); document.write( "t = 3.5 hrs
\n" ); document.write( "but they want it in minutes: 3.5 * 60 = 210 minutes
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\n" ); document.write( "Check solution by finding the distances
\n" ); document.write( "3.5(50) = 175 mi
\n" ); document.write( "3.5(30) = 105 mi
\n" ); document.write( "-----------------
\n" ); document.write( "differs: 70 mi
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