document.write( "Question 358691: the length of the rectangle is 5yd more then its width, the area of the rectangle is 88yd^2. find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #256018 by checkley77(12844)\"\" \"About 
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L=W+5
\n" ); document.write( "LW=88
\n" ); document.write( "(W+5)W=88
\n" ); document.write( "W^2+5W=88
\n" ); document.write( "W^2+5W-88=0
\n" ); document.write( "\"w+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "w=(-5+-sqrt[5^2-4*1*-88])/2*1
\n" ); document.write( "w=(-5+-sqrt[25+352])/2
\n" ); document.write( "w=(-5+-sqrt377)/2
\n" ); document.write( "w=(-5+-19.4165)/2
\n" ); document.write( "w=(-5+19.4165)/2
\n" ); document.write( "w=14.4165/2
\n" ); document.write( "w=7.2 ANS.
\n" ); document.write( "w=(-5-19.4165)/2
\n" ); document.write( "w=(-24.4165/2
\n" ); document.write( "w=-12.2 ans.
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