document.write( "Question 358691: the length of the rectangle is 5yd more then its width, the area of the rectangle is 88yd^2. find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #256018 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+5 \n" ); document.write( "LW=88 \n" ); document.write( "(W+5)W=88 \n" ); document.write( "W^2+5W=88 \n" ); document.write( "W^2+5W-88=0 \n" ); document.write( " \n" ); document.write( "w=(-5+-sqrt[5^2-4*1*-88])/2*1 \n" ); document.write( "w=(-5+-sqrt[25+352])/2 \n" ); document.write( "w=(-5+-sqrt377)/2 \n" ); document.write( "w=(-5+-19.4165)/2 \n" ); document.write( "w=(-5+19.4165)/2 \n" ); document.write( "w=14.4165/2 \n" ); document.write( "w=7.2 ANS. \n" ); document.write( "w=(-5-19.4165)/2 \n" ); document.write( "w=(-24.4165/2 \n" ); document.write( "w=-12.2 ans. \n" ); document.write( " |