document.write( "Question 358715: how much of a 50% acid solution must be mixed with 30 gallons of a 19% acid solution to obtain a solution that is 40% acid? \n" ); document.write( "
Algebra.Com's Answer #256007 by checkley77(12844)\"\" \"About 
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.50X+.19*30=.40(30+X)
\n" ); document.write( ".50X+5.7=12+.40X
\n" ); document.write( ".50X-.40X=12-5.7
\n" ); document.write( ".10X=6.3
\n" ); document.write( "X=6.3/.10
\n" ); document.write( "X=63 GALLONS OF 50% ACID SOLUTION IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".50*63+.19*30=.40(30+63)
\n" ); document.write( "31.5+5.7=.40*93
\n" ); document.write( "37.2=37.2\r
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