document.write( "Question 358715: how much of a 50% acid solution must be mixed with 30 gallons of a 19% acid solution to obtain a solution that is 40% acid? \n" ); document.write( "
Algebra.Com's Answer #256007 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .50X+.19*30=.40(30+X) \n" ); document.write( ".50X+5.7=12+.40X \n" ); document.write( ".50X-.40X=12-5.7 \n" ); document.write( ".10X=6.3 \n" ); document.write( "X=6.3/.10 \n" ); document.write( "X=63 GALLONS OF 50% ACID SOLUTION IS USED. \n" ); document.write( "PROOF: \n" ); document.write( ".50*63+.19*30=.40(30+63) \n" ); document.write( "31.5+5.7=.40*93 \n" ); document.write( "37.2=37.2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |