document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=358647>Question 358647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 52 feet. Describe the possible lengths of a side if the area of the rectangle is not to exceed 120 square feet </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #255982 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=255982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+2y=52<BR>\n" );
document.write( "xy=120 or x=120/y<BR>\n" );
document.write( "2(120/y)+2y=52<BR>\n" );
document.write( "240/y+2y=52<BR>\n" );
document.write( "(240+2y*y)/y=52<BR>\n" );
document.write( "(240+2y^2)/y=52 cross multiply.<BR>\n" );
document.write( "2y^2+240=52y<BR>\n" );
document.write( "2y^2-52y+240=0<BR>\n" );
document.write( "2(y^2-26y+120)=0<BR>\n" );
document.write( "2(y-20)(y-6)=0<BR>\n" );
document.write( "y-20=0<BR>\n" );
document.write( "y=20 ans. <BR>\n" );
document.write( "x=120/20=6 ans.<BR>\n" );
document.write( "y-6=0<BR>\n" );
document.write( "y=6 ans.<BR>\n" );
document.write( "x=120/6=20 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "20*6=120 ans. area.<BR>\n" );
document.write( "2*20+2*6=40+12=52 ans. perimeter. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );