document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=358588>Question 358588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cattle train left Miami and traveled toward New York. 14 hours later a diesel train left traveling at 45 km/h in an effort to catch up to the cattle train. After traveling for four hours the diesel train finally caught up. What was the cattle trains average speed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #255952 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=255952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance = rate * time or rate=distance/time or time=distance/rate<BR>\n" );
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document.write( "The deisel train catches up to the cattle train. That means they travel the same distance at that instance.<BR>\n" );
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document.write( "The distance travelled by the deisel train:  d=r*t=45mph*4hours=180 miles<BR>\n" );
document.write( "It also means that the cattle train travel 180 miles when they were together.<BR>\n" );
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document.write( "But the cattle train had travelled for an additional 14 hours or a total of 14+4 =18 hours<BR>\n" );
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document.write( "Cattle rate (or speed)=d/t=180miles/18hours=10mph\r<BR>\n" );
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