document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=358557>Question 358557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line with a slope of -1/3 and passing through the point (6, -4). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #255891 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=255891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the point-slope form of a line, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-y%5Bp%5D=m%28x-x%5Bp%5D%29 ALIGN=MIDDLE  ALT=\"y-y%5Bp%5D=m%28x-x%5Bp%5D%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-%28-4%29=-%281%2F3%29%28x-6%29 ALIGN=MIDDLE  ALT=\"y-%28-4%29=-%281%2F3%29%28x-6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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