document.write( "Question 358516: mrs. williams mixed nuts that cost $3.90 per pound with nuts that cost $4.30 per pound to obtain a mixture of 50 pounds of nuts worth $4.20 per pound. how many pounds of each type of nuts did she use? \n" ); document.write( "

Algebra.Com's Answer #255865 by CharlesG2(834) $\"\"$ $\"About$

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mrs. williams mixed nuts that cost $3.90 per pound with nuts that cost $4.30 per pound to obtain a mixture of 50 pounds of nuts worth $4.20 per pound. how many pounds of each type of nuts did she use?\r
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\n" ); document.write( "\n" ); document.write( "price/lb A * amount A + price/lb B * amount B = price/lb C * amount C
\n" ); document.write( "$3.90/lb * A + $4.30/lb * B = $4.20/lb * C
\n" ); document.write( "let amount C = amount A + amount B = 50 lbs, let amount B = 50 - A lbs
\n" ); document.write( "3.90A + 4.30(50 - A) = 4.20(50)
\n" ); document.write( "3.90A + 215 - 4.30A = 210
\n" ); document.write( "-0.40A = -5
\n" ); document.write( "0.40A = 5 (divided the -1 out)
\n" ); document.write( "A = 12.5 lbs of one type of nuts
\n" ); document.write( "B = 50 - A = 50 - 12.5 = 37.5 lbs of the other type of nut
\n" ); document.write( "we could tell before solving anything that there was going to be more of the $4.30 nuts than the $3.90 nuts since $4.30 is closer to $4.20 than $3.90 is
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