document.write( "Question 358440: The area of a triangular sheet of paper is 190 square inches. One side of the triangle is 8 inches more than three times the length of the altitude to that side. Find the length of that side and the altitude to the side. \n" ); document.write( "
Algebra.Com's Answer #255808 by mananth(16946)\"\" \"About 
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The area of a triangular sheet of paper is 190 square inches. One side of the triangle is 8 inches more than three times the length of the altitude to that side. Find the length of that side and the altitude to the side.
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\n" ); document.write( "let altitude be x
\n" ); document.write( "the base = 3x+8
\n" ); document.write( "Area = 190 m^2
\n" ); document.write( "...
\n" ); document.write( "1/2 * x * (3x+8) = 190
\n" ); document.write( "multiply by 2
\n" ); document.write( "x(3x+8)=190*2
\n" ); document.write( "3x^2+8x=380
\n" ); document.write( "3x^2+8x-380=0
\n" ); document.write( "use the quadratic equation to find the roots x1 & x2\r
\n" ); document.write( "\n" ); document.write( "b^2-4ac = 4624
\n" ); document.write( "x1=(-8+sqrt(4624))/2
\n" ); document.write( "x1=10 inches the altitude
\n" ); document.write( "x2 =negative so ignore
\n" ); document.write( "base = 3*10+8 = 38 inches\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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