document.write( "Question 5021: the sum of the digits of a two-digit number is 12. if the digits are reversed, the new number is 18 less than the original number. find the original number. \n" ); document.write( "
Algebra.Com's Answer #2558 by rapaljer(4671)\"\" \"About 
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Let t = tens digit
\n" ); document.write( "u = units digit
\n" ); document.write( "10t + u = value of the number
\n" ); document.write( "10u + t = value of the number with digits reversed\r
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\n" ); document.write( "\n" ); document.write( "Two equations:
\n" ); document.write( "\"Sum of the digits is 12.\"
\n" ); document.write( "t+u = 12 FIRST EQUATION\r
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\n" ); document.write( "\n" ); document.write( "\"If the digits are reversed, the new number is 18 less than the original number.\" OR \"Reversed number = original number - 18\"\r
\n" ); document.write( "\n" ); document.write( "10u + t = 10t + u - 18
\n" ); document.write( "9u - 9t = - 18\r
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\n" ); document.write( "\n" ); document.write( "Divide by 9:
\n" ); document.write( "u - t = -2 SECOND EQUATION
\n" ); document.write( "u + t = 12 FIRST EQUATION\r
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\n" ); document.write( "\n" ); document.write( "Add equations together:
\n" ); document.write( "2u = 10
\n" ); document.write( "u = 5\r
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\n" ); document.write( "\n" ); document.write( "u+t = 12
\n" ); document.write( "5 + t = 12
\n" ); document.write( "t = 7\r
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\n" ); document.write( "\n" ); document.write( "Original number = 75
\n" ); document.write( "Reverse digits = 57\r
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\n" ); document.write( "\n" ); document.write( "Check: If you reverse the digits, the NEW NUMBER IS 18 less than ORIGINAL NUMBER. Observe, the new number IS 57 which is 18 less than 75. It checks!!!\r
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