document.write( "Question 5021: the sum of the digits of a two-digit number is 12. if the digits are reversed, the new number is 18 less than the original number. find the original number. \n" ); document.write( "
Algebra.Com's Answer #2558 by rapaljer(4671) You can put this solution on YOUR website! Let t = tens digit \n" ); document.write( "u = units digit \n" ); document.write( "10t + u = value of the number \n" ); document.write( "10u + t = value of the number with digits reversed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Two equations: \n" ); document.write( "\"Sum of the digits is 12.\" \n" ); document.write( "t+u = 12 FIRST EQUATION\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"If the digits are reversed, the new number is 18 less than the original number.\" OR \"Reversed number = original number - 18\"\r \n" ); document.write( "\n" ); document.write( "10u + t = 10t + u - 18 \n" ); document.write( "9u - 9t = - 18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide by 9: \n" ); document.write( "u - t = -2 SECOND EQUATION \n" ); document.write( "u + t = 12 FIRST EQUATION\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add equations together: \n" ); document.write( "2u = 10 \n" ); document.write( "u = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "u+t = 12 \n" ); document.write( "5 + t = 12 \n" ); document.write( "t = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Original number = 75 \n" ); document.write( "Reverse digits = 57\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: If you reverse the digits, the NEW NUMBER IS 18 less than ORIGINAL NUMBER. Observe, the new number IS 57 which is 18 less than 75. It checks!!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |