document.write( "Question 358404: The length of a rectangle is five more than twice its
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document.write( "width. The area of the rectangle is 52 sqm. Find the
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document.write( "dimensions of the rectangle. \n" );
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Algebra.Com's Answer #255786 by sudhanshu_kmr(1152)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "Let width is x, then length = 2x+5\r \n" ); document.write( "\n" ); document.write( " x(2x+5) = 52\r \n" ); document.write( "\n" ); document.write( " => 2x^2 +5x -52 = 0\r \n" ); document.write( "\n" ); document.write( " => 2x^2 +13x - 8x -52 = 0\r \n" ); document.write( "\n" ); document.write( " => x(2x + 13) -4(2x + 13) = 0\r \n" ); document.write( "\n" ); document.write( " => (x-4) (2x+13) = 0\r \n" ); document.write( "\n" ); document.write( "hence x =4, 2x+5 = 13\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "dimensions are 4 and 13. \n" ); document.write( " |