document.write( "Question 358404: The length of a rectangle is five more than twice its
\n" );
document.write( "width. The area of the rectangle is 52 sqm. Find the
\n" );
document.write( "dimensions of the rectangle. \n" );
document.write( "
Algebra.Com's Answer #255784 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let width be x \n" ); document.write( "length = 2x+5 \n" ); document.write( "area = 52 m^2 \n" ); document.write( "Area = L*W \n" ); document.write( "x(2x+5)=52 \n" ); document.write( "2x^2+5x=52 \n" ); document.write( "2x^2+5x-52=0\r \n" ); document.write( "\n" ); document.write( "2x^2-8x+13x-52=0 \n" ); document.write( "2x(x-4)+13(x-4)=0 \n" ); document.write( "(x-4)(2x+13)=0 \n" ); document.write( "x=4 x = -6.5(ignore) \n" ); document.write( "width = 4 \n" ); document.write( "length = 2x+5 = 13 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |