document.write( "Question 358404: The length of a rectangle is five more than twice its
\n" ); document.write( "width. The area of the rectangle is 52 sqm. Find the
\n" ); document.write( "dimensions of the rectangle.
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Algebra.Com's Answer #255784 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let width be x
\n" ); document.write( "length = 2x+5
\n" ); document.write( "area = 52 m^2
\n" ); document.write( "Area = L*W
\n" ); document.write( "x(2x+5)=52
\n" ); document.write( "2x^2+5x=52
\n" ); document.write( "2x^2+5x-52=0\r
\n" ); document.write( "\n" ); document.write( "2x^2-8x+13x-52=0
\n" ); document.write( "2x(x-4)+13(x-4)=0
\n" ); document.write( "(x-4)(2x+13)=0
\n" ); document.write( "x=4 x = -6.5(ignore)
\n" ); document.write( "width = 4
\n" ); document.write( "length = 2x+5 = 13
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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