document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=358418>Question 358418</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is 3 more than twice another number. If their sum is 21, find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #255780 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=255780\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one number be x<BR>\n" );
document.write( "the other number will be 2x+3<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x+2x+3=21<BR>\n" );
document.write( "3x+3=21<BR>\n" );
document.write( "-3<BR>\n" );
document.write( "3x=21-3<BR>\n" );
document.write( "3x=18<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "x=18/3<BR>\n" );
document.write( "x= 3<BR>\n" );
document.write( "..<BR>\n" );
document.write( "the other number = 2x+3= 6+3=9<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );