document.write( "Question 358387: In a rectangle the lenght is 2cm longer than it's width & a diagonal is 10cm. What is the area??\r
\n" ); document.write( "\n" ); document.write( "PLease tell me the answer and how did u get it. ^^ tnx \n" ); document.write( "
Algebra.Com's Answer #255770 by mananth(16946)\"\" \"About 
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In a rectangle the lenght is 2cm longer than it's width & a diagonal is 10cm. What is the area??
\n" ); document.write( "let the width be x cm
\n" ); document.write( "length = x+2 cm.
\n" ); document.write( "..
\n" ); document.write( "diagonal = 10 cm.
\n" ); document.write( "the diagonal and the sides of the rectangle form a right triangle with diagonal as the hypotenuse.
\n" ); document.write( "use pythagoras theorem
\n" ); document.write( ".
\n" ); document.write( "leg1^2+leg2^2= hypo^2
\n" ); document.write( "x^2+(x+2)^2= 10^2
\n" ); document.write( "x^2+x^2+4x+4 = 100
\n" ); document.write( "2x^2+4x+4-100=0
\n" ); document.write( "2x^2+4x-96=0
\n" ); document.write( "/2
\n" ); document.write( "x^2+2x-48=0
\n" ); document.write( "x^2+8x-6x-48=0
\n" ); document.write( "x(x+8)-6(x+8)=0
\n" ); document.write( "(x+8)(x-6)=0
\n" ); document.write( "x=6 which is positve
\n" ); document.write( "width 6 cm
\n" ); document.write( "length = 8 cm.
\n" ); document.write( "Area = L*W
\n" ); document.write( "Area = 6*8=48 cm^2
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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