document.write( "Question 358332: Fifteen years from now Mr. Thomas will be twice as old as Mrs. Thomas is now; whereas Mrs. Thomas will then be as old as Mr. Thomas will be 10 years from now. How old are Mr. and Mrs. Thomas now \n" ); document.write( "
Algebra.Com's Answer #255720 by stanbon(75887)\"\" \"About 
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Fifteen years from now Mr. Thomas will be twice as old as Mrs. Thomas is now; whereas Mrs. Thomas will then be as old as Mr. Thomas will be 10 years from now. How old are Mr. and Mrs. Thomas now
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\n" ); document.write( "Let Mr. be R
\n" ); document.write( "Let Mrs. be S
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\n" ); document.write( "(R+15) = 2(S)
\n" ); document.write( "(S+15) = R+10
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\n" ); document.write( "R = 2S - 15
\n" ); document.write( "Substitute for R and solve for \"S\":
\n" ); document.write( "S+15 = 2S-15+10
\n" ); document.write( "S+15 = 2S-5
\n" ); document.write( "S = 20 yrs (Mrs. Thomas's age now)
\n" ); document.write( "Since R = 2S-15, R = 2*20-15, R = 25 yrs (Mr. Thomas's age now)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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