document.write( "Question 358296: How do you solve the system equation?
\n" ); document.write( "6a+ 2b= 11
\n" ); document.write( "3a= 8b+ 1
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Algebra.Com's Answer #255690 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Adding the two equations in the system together & solving by eliminating one of the variables
\n" ); document.write( "6a+ 2b= 11
\n" ); document.write( "3a= 8b+ 1
\n" ); document.write( "arranging in like form
\n" ); document.write( "6a + 2b= 11
\n" ); document.write( "3a - 8b= 1\r
\n" ); document.write( "\n" ); document.write( "Multiplying first equation thru by 4
\n" ); document.write( "24a + 8b= 44
\n" ); document.write( "3a - 8b = 1\r
\n" ); document.write( "\n" ); document.write( "adding the two equation together (eliminating b variable)
\n" ); document.write( "27a = 45
\n" ); document.write( "a = 45/27 = 5/3
\n" ); document.write( "Solving for the b substituting a = 5/3
\n" ); document.write( "3a = 8b +1
\n" ); document.write( "5 = 8b + 1
\n" ); document.write( "4 = 8b
\n" ); document.write( "1/2 = b
\n" ); document.write( "checkiing the answer using one of the equation
\n" ); document.write( "24(5/3) + 8*(1/2) = 40 + 4 = 44 \n" ); document.write( "
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