document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40139>Question 40139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE GRAZING GOAT\r<BR>\n" );
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document.write( "Zoe the goat is tied by a rope to one corner of a 15 meter by 25 meter barn in the middle of a large, grassy field. Over what area of the field can Zoe graze if the rope is:\r<BR>\n" );
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document.write( "a) 10 meters long?\r<BR>\n" );
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document.write( "b) 20 meters long?\r<BR>\n" );
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document.write( "c) 30 meters long?\r<BR>\n" );
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document.write( "d) 40 meters long?\r<BR>\n" );
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document.write( "e) Zoe is happiest when she has at least 400 m2 to graze. What possible lengths of rope could be used?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25569 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25569\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=PI*R~2 OR A=3.14*10083/4 OR A=235.5 M~2 FOR THE 10 M ROPE \r<BR>\n" );
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document.write( "A=PI*400*3/4+PI*100*1/4 OR A=1020.5 ZOE IS HAPPY WITH AT LEAST A 20 M ROPE </SPAN>\n" );
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