document.write( "Question 358073: Twice the small number is 5 more than 2/3 the larger number. Three times the larger number is 4 less than 15 times the smaller number. Find the value of both numbers. \n" ); document.write( "
Algebra.Com's Answer #255658 by ankor@dixie-net.com(22740)\"\" \"About 
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Let x = the large number
\n" ); document.write( "Let y = the small number
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "Twice the small number is 5 more than 2/3 the larger number.
\n" ); document.write( "2y = \"2%2F3\"x + 5
\n" ); document.write( "Get rid of that annoying fraction, multiply by 3, results:
\n" ); document.write( "6y = 2x + 15
\n" ); document.write( "-2x + 6y = 15
\n" ); document.write( ":
\n" ); document.write( " Three times the larger number is 4 less than 15 times the smaller number.
\n" ); document.write( "3x = 15y - 4
\n" ); document.write( "3x - 15y = -4
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\n" ); document.write( "Use elimination here, multiply the 1st equation by 3, and the 2nd equation by 2
\n" ); document.write( "-6x + 18y = 45
\n" ); document.write( "+6x - 20y = -8
\n" ); document.write( "-------------------adding eliminates x, find y
\n" ); document.write( "-12y = 37
\n" ); document.write( "y = \"-37%2F12\"
\n" ); document.write( ":
\n" ); document.write( "Use the 1st equation to find x
\n" ); document.write( "-2x + 6(\"-37%2F12\") = 15
\n" ); document.write( "-2x + \"-37%2F2\") = 15
\n" ); document.write( "Multiply by 2
\n" ); document.write( "-4x - 37 = 30
\n" ); document.write( "-4x = 30 + 37
\n" ); document.write( "-4x = 67
\n" ); document.write( "x = \"-67%2F4\"
\n" ); document.write( ":
\n" ); document.write( "A couple nasty fractions, see if they work in the 2nd equation
\n" ); document.write( "3x - 15y = -4
\n" ); document.write( "Substitute
\n" ); document.write( "3(\"-67%2F4\") - 15(\"-37%2F12\" = -4
\n" ); document.write( "\"-201%2F4\" + (\"555%2F12\" = -4
\n" ); document.write( "multiply by 12 to get rid of those annoying fractions
\n" ); document.write( "3(201) + 555 = -48
\n" ); document.write( "-603 + 555 = -48; it does work, amazing isn't it!
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