document.write( "Question 358173: Using the digits 0,1,2,3,4 and 5, how many 5 digit odd numbers are possible if repetition is no allowed? \n" ); document.write( "
Algebra.Com's Answer #255646 by Edwin McCravy(20055)\"\" \"About 
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document.write( "A random one would be  \r\n" );
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document.write( "45203\r\n" );
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document.write( "We begin by choosing the last, or 5th, digit first.  An odd number must end with\r\n" );
document.write( "an odd digit, and the only odd ones are 1, 3, and 5, so there are 3 ways to\r\n" );
document.write( " choose the last digit.\r\n" );
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document.write( "Next we will choose the first digit.  It cannot be 0, so it is one of these:\r\n" );
document.write( "1,2,3,4,5, but it cannot be the odd digit that we chose for the 5th digit.\r\n" );
document.write( "So there are 4 ways left to choose the 1st digit.\r\n" );
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document.write( "The other digits can be a 0, so there are 4 ways left to choose the 2nd digit.\r\n" );
document.write( "Then there are then 3 ways left to choose the 3rd digit.\r\n" );
document.write( "Then there are then 2 ways left to choose the 4th digit.\r\n" );
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document.write( "That's 3*4*4*3*2 = 288\r\n" );
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document.write( "Edwin
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