document.write( "Question 40139: THE GRAZING GOAT\r
\n" ); document.write( "\n" ); document.write( "Zoe the goat is tied by a rope to one corner of a 15 meter by 25 meter barn in the middle of a large, grassy field. Over what area of the field can Zoe graze if the rope is:\r
\n" ); document.write( "\n" ); document.write( "a) 10 meters long?\r
\n" ); document.write( "\n" ); document.write( "b) 20 meters long?\r
\n" ); document.write( "\n" ); document.write( "c) 30 meters long?\r
\n" ); document.write( "\n" ); document.write( "d) 40 meters long?\r
\n" ); document.write( "\n" ); document.write( "e) Zoe is happiest when she has at least 400 m2 to graze. What possible lengths of rope could be used?\r
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Algebra.Com's Answer #25564 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
The area of the barn is: 15*25 = 375 squared meters
\n" ); document.write( "The area of the stretch of rope is:
\n" ); document.write( "\"A+=+%28pi%29r%5E2%2F4\" because it is a fourth of the area of a circle
\n" ); document.write( "a) 10 meters long?
\n" ); document.write( "\"A+=+%28pi%29100%2F4\"
\n" ); document.write( "\"A+=+%28pi%2925\" about 78.54 squared meters
\n" ); document.write( "I think you can do the rest with the formula presented.
\n" ); document.write( "e) Zoe is happiest when she has at least 400 m2 to graze. What possible lengths of rope could be used?
\n" ); document.write( "\"400+%3C=+%28pi%29r%5E2%2F4\"
\n" ); document.write( "\"1600%2F%28pi%29+%3C=+r%5E2\"
\n" ); document.write( "\"sqrt%281600%2F%28pi%29%29+%3C=+r\"
\n" ); document.write( "\"22.57+%3C=+r\"
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