document.write( "Question 358065: Andrew drove at an average speed of 56 mph over six hours. During the first three hours, he drove at a speed that was sixty-eight mph less than two times the speed he averaged for the last three hours. How fast did he drive during the first three hours? \n" ); document.write( "
Algebra.Com's Answer #255599 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 3(2X-68)+3X=56*6 \n" ); document.write( "6X-204+3X=336 \n" ); document.write( "9X=336+204 \n" ); document.write( "9X=540 \n" ); document.write( "X=540/9 \n" ); document.write( "X=60 MPH. FOR THE SECOND PART OF THE TRIP. \n" ); document.write( "2*60-68=120-68=52 MPH. FOR THE FIRST PART OF THE TRIP. \n" ); document.write( "PROOF \n" ); document.write( "3*52+3*60=56*6 \n" ); document.write( "156+180=336 \n" ); document.write( "336=336 \n" ); document.write( " \n" ); document.write( " |