document.write( "Question 358065: Andrew drove at an average speed of 56 mph over six hours. During the first three hours, he drove at a speed that was sixty-eight mph less than two times the speed he averaged for the last three hours. How fast did he drive during the first three hours? \n" ); document.write( "
Algebra.Com's Answer #255599 by checkley77(12844)\"\" \"About 
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3(2X-68)+3X=56*6
\n" ); document.write( "6X-204+3X=336
\n" ); document.write( "9X=336+204
\n" ); document.write( "9X=540
\n" ); document.write( "X=540/9
\n" ); document.write( "X=60 MPH. FOR THE SECOND PART OF THE TRIP.
\n" ); document.write( "2*60-68=120-68=52 MPH. FOR THE FIRST PART OF THE TRIP.
\n" ); document.write( "PROOF
\n" ); document.write( "3*52+3*60=56*6
\n" ); document.write( "156+180=336
\n" ); document.write( "336=336
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