document.write( "Question 358061: Hi
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document.write( " Quick question if somebody would be so kind as to walk me through it\r
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document.write( "Find the equation of the tangent to the circle\r
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document.write( "x^2+y^2-4y-1=0\r
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document.write( "The the point (2,1)\r
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document.write( "Thanks in advance \n" );
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Algebra.Com's Answer #255596 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the equation of the tangent to the circle \n" ); document.write( "x^2+y^2-4y-1=0 \n" ); document.write( "The the point (2,1) \n" ); document.write( "------------------ \n" ); document.write( "Find the derivative. \n" ); document.write( "2x + 2yy' - 4y' = 0 \n" ); document.write( "y'(2y-4) = -2x \n" ); document.write( "--- \n" ); document.write( "y' = -2x/(2y-4) \n" ); document.write( "This is the slope at every point (x,y) \n" ); document.write( "-------------------------------------------- \n" ); document.write( "Let x = 2 ; Let y = 1 to find the slope at (2,1) \n" ); document.write( "y' = -4/(-2) = 2 \n" ); document.write( "---- \n" ); document.write( "Find the line with slope = 2 passing thru (2,1) \n" ); document.write( "1 = -2(2)+b \n" ); document.write( "b = 5 \n" ); document.write( "------- \n" ); document.write( "Equation of the tangent at (2,1) \n" ); document.write( "y = 2x+5 \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========================================= \n" ); document.write( " |