document.write( "Question 358029: A miller wishes to make 140 bushels of a mixture of corn and oats to sell at $1.20 a bushel. If a bushel of oats is worth 80 cents and a bushel of corn is worth $1.50, how many bushels of each should he use? \n" ); document.write( "

Algebra.Com's Answer #255570 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x be the number of bushels of the 1.50/bushel corn.  Then (140-x) would be the number of bushels for the 080/bushel corn
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document.write( "1.50 x +  .80(140-x) = 1.20*140
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document.write( "1.50x + .80*140 -.8x = 1.20*140
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document.write( ".7x = .4*140
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document.write( "x = 80 bushels of the 1.50/bushel corn
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document.write( "(140-x) = 60 bushels of the .80/bushel corn
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document.write( "check your answer
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document.write( "1.5*80 + .80*60 = 120 + 48  =168 \n" );
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